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probability betting strategy and remain with 1.6 odds per day



 This market will assist in maintaining (1.6 odds) a less risky outcome.

What if you could get (1.6 odds free based on mathematical strategy)?

distinct selection and strategy. I have been exercising it in the low season. All you need to do is select two teams and pick odd on team one and even on team two. Do it the other way around to remain with two possible outcomes. In mathematics, if two teams have two winning options, the total outcome is four. This is probability.

What I mean

example, Manchester playing against Brighton, even or odd market, we have two options. If you bet on one team both odd and even separately you will make a loss because this market has 1.85 odds. But if you combine two teams you will get a profit but remember it have four outcomes. you must exclude two outcomes This is where I am coming to share my tip, to show you how to reduce these outcomes to two. which are odd, even, and even , odd and strange You will have to place two bet slips, each having a total of 3.4 odds, and you are going to make a profit. It may seem easy, but without unique knowledge and experience, you may end up losing your money.

take this example below.

check this first two EPL teams, yesterday i staked 20USD (2,000 ksh). In betslip one i picked( even , odd) staked 10USD. in bet two i picked (odd and even) and staked the same. one betslip lost and the other one made a profit of 14USD . (10USD x 3.4 odds) win 34USD which is ksh 3400



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